- #1

- 45

- 0

a)0.20m/s

b)0.41m/s

c)0.10m/s

My Work :

And stops at the top => v=0 and h=5m so I'll use mgh.

Now power output = variation of energy/1

But average means the variation of x /variation in time.

Any help will be great,

Thanks

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- Thread starter -Aladdin-
- Start date

- #1

- 45

- 0

a)0.20m/s

b)0.41m/s

c)0.10m/s

My Work :

And stops at the top => v=0 and h=5m so I'll use mgh.

Now power output = variation of energy/1

But average means the variation of x /variation in time.

Any help will be great,

Thanks

- #2

Doc Al

Mentor

- 45,251

- 1,603

How much work does she have to do to climb the rope? In what time must she complete the climb to have her average power equal 200 W?

- #3

- 45

- 0

Work = mgh , where h=5

Power = Work/time

time = Work / power

Average speed = 5 / time(gotten) ?

- #4

Doc Al

Mentor

- 45,251

- 1,603

Sounds good to me.

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